Verified:

archaic Game profile

Member
7014

May 27th 2014, 18:15:33

Discuss




(apparently QZ has disabled ASCII greek letters)
Cheating Mod Hall of Shame: Dark Morbid, Turtle Crawler, Sov

martian Game profile

Game Moderator
Mod Boss
7841

May 27th 2014, 18:20:38

easy proof of this identity:

let A be the adjacent side of the right angle triangle
and O be the opposite side of the right angle triangle
and H be the hypotenuse (no you are a hypotenuse).
Then sin (a) = O/H and cos(a) = (A/H)
sin^2(a) + cos^2(a) = O^2/H^2 + A^2/H^2 = (O^2 + A^2)/H^2
O^2 + A^2 = H^2 by pythagoras and martian law
so (O^2+A^2)/H^2 = H^2/H^2 = 1.

LARRRRS!

you are all special in the eyes of fluff
(|(|
( ._.) -----)-->
(_(' )(' )

RUN IT IS A KILLER BUNNY!!!

martian Game profile

Game Moderator
Mod Boss
7841

May 27th 2014, 18:21:25

this only proves the identity for a being a real number :P
you are all special in the eyes of fluff
(|(|
( ._.) -----)-->
(_(' )(' )

RUN IT IS A KILLER BUNNY!!!

Akula Game profile

Member
EE Patron
4113

May 27th 2014, 18:54:37

a = 2 π n + π, n ϵ Z

greek letters work fine for me off char map
=============================
"Astra inclinant, sed non obligant"

SOL http://sol.ghqnet.com/
=============================

EricEazyE

Member
45

May 27th 2014, 21:11:24

I don't understand any of this.

¯\_(ツ)_/¯

Member
44

May 27th 2014, 21:30:12

qz better not had deactivated my nickname!

Akula Game profile

Member
EE Patron
4113

May 27th 2014, 21:30:38

yer history !
=============================
"Astra inclinant, sed non obligant"

SOL http://sol.ghqnet.com/
=============================

ಠ_ಠ

New Member
13

May 27th 2014, 21:33:33

does the look of disapproval live on?

ಠ_ಠ

New Member
13

May 27th 2014, 21:33:42

[quote poster=ಠ_ಠ; 31625; 570589]does the look of disapproval live on? [/quote]

HE DOOOOOOOOOOOOOOOOOOO

ಠ_ಠ

New Member
13

May 27th 2014, 21:34:37

┌─┐
┴─┴
ಠ_ರೃ


pimpin'

downsay Game profile

Member
103

May 28th 2014, 2:30:24

love the hat